Sagarin Based Bowl Pick'Em Sheet

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December 10th, 2012 at 5:04 PM
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club_med
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Joined: 05/20/2010
MGoPoints: 318
Sagarin Based Bowl Pick'Em Sheet

Sometime a couple of years ago, someone on the board created a Bowl Pick'em spreadsheet that used Sagarin ratings to create a "Watchability index" that looked for games where Sagarin predicted close games and used this budget his time over the holidays, and also to help him pick winners. I haven't seen anyone post this yet this year, so I figured I'd go ahead and make one up. 

Here is a link to the spreadsheet. It is setup to work with the Yahoo Sports system, so the games are sorted in order of most confident picks (Arizona State over Navy) to least confident (Northwestern of Mississippi State). There's a "PREDICTOR Pick" column which indicates which team the PREDICTOR model would pick to win the game (Sagarin regards PREDICTOR as the best model of game outcomes). If you prefer, you can also pick by RATING and ELO_CHESS differences using the appropriate columns in the sheet. Enjoy.

the crowds on the shore will always yell "Let's Go Blue."

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December 10th, 2012 at 5:34 PM | Interesting that NW over (Score:2)
unWavering
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Joined: 01/13/2011
MGoPoints: 1766

Interesting that NW over Mississippi State is the least confident pick.  I may be biased, but I think NW will beat them pretty easily.  Mississippi State hasn't beaten anybody, and while NW hasn't really either, they really aren't that far from being 12-0.

EDIT:  D'oh, it has Mississippi State over NW.  But still, I think NW should take this game.

December 10th, 2012 at 5:18 PM | If I'm reading this (Score:2)
uniqenam
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Joined: 07/20/2009
MGoPoints: 2397

If I'm reading this spreadsheet correctly, then no B1G team is favored to win their bowl game. Should be an interesting bowl season!

I miss King of Belch.

December 10th, 2012 at 5:23 PM | Northwestern and....Rutgers, (Score:2)
club_med
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Joined: 05/20/2010
MGoPoints: 318

Northwestern and....Rutgers, I guess. The "Underdog" column is based on Yahoo's classifcation, not Sagarin's.

the crowds on the shore will always yell "Let's Go Blue."

December 10th, 2012 at 5:25 PM | Ah yes, thank you...brain (Score:2)
uniqenam
uniqenam's picture
Joined: 07/20/2009
MGoPoints: 2397

Ah yes, thank you...brain fried from a long day in lab.

I miss King of Belch.

December 10th, 2012 at 5:41 PM | Cool looking spreadsheet (Score:2)
The Barwis Effect
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Joined: 06/30/2008
MGoPoints: 2244

What exactly does it tell me though? Color me confused.

"[T]here were a lot of people predicting glorious heights for Rich; mostly the same people who are predicting doom and gloom [for Hoke]. Excuse me if I doubt their prognostication skills." -- M-Wolverine

December 10th, 2012 at 5:52 PM | The "PREDICTOR Pick" column (Score:2)
club_med
club_med's picture
Joined: 05/20/2010
MGoPoints: 318

The "PREDICTOR Pick" column on the far right tells you who Sagarin's PREDICTOR model says should win the game, and the "PREDICTOR dIfference" column tells you by how much. Games at the top of the list should be blowouts, the games at the bottom should be close.

the crowds on the shore will always yell "Let's Go Blue."

December 10th, 2012 at 6:02 PM | :) (Score:2)
The Barwis Effect
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Joined: 06/30/2008
MGoPoints: 2244

Thanks!!!

"[T]here were a lot of people predicting glorious heights for Rich; mostly the same people who are predicting doom and gloom [for Hoke]. Excuse me if I doubt their prognostication skills." -- M-Wolverine

December 10th, 2012 at 6:47 PM | So, By Conference... (Score:2)
LSAClassOf2000
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Joined: 01/07/2011
MGoPoints: 8754

Basically, using the Sagarin predictors,  the Pac-12, Big XII and SEC are estimated to win six bowls each, the SunBelt could potentially win four, and the WAC, MWC and Big East are predicted to walk away with two each, if the model ends up to be totally spot on. The MAC, C-USA, ACC and the Big Ten are favored in only one. Then, of course, there is BYU. Another action-packed bowl season ahead, from the sound of it. 

"Funny isn't it, how naughty dentists always make that one fatal mistake."

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December 10th, 2012 at 9:23 PM | a quibble (Score:2)
Yeoman
Joined: 06/08/2011
MGoPoints: 2248

expected wins <> # of bowls favored in.

If you have 4 teams each with a 48% chance of winning, your expected wins are just under two but you aren't favored in any of them.

December 10th, 2012 at 9:28 PM | this bowl thing (Score:1)
MGlobules
Joined: 11/17/2008
MGoPoints: 5163

is a mug's game for the Big Ten. The problem is that we've got less to complain about this year than many years, and our teams are so bad we still may lose big. Sigh. 

December 11th, 2012 at 10:28 AM | I feel like the Big Ten, (Score:1)
ontarioblue
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Joined: 06/30/2008
MGoPoints: 1237

I can't find the link.  I lost even before I started.

December 11th, 2012 at 12:56 PM | "Here" (Score:1)
BlueMars24
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Joined: 03/28/2011
MGoPoints: 146

It's right there on the here

Those who stay will be champions

December 11th, 2012 at 3:41 PM | consider the variation as well as deviation from expected wins (Score:1)
michelin
Joined: 09/22/2009
MGoPoints: 479

To measure the luckiness (or surprise value) of a season record, you might want to consider the standard deviation as well as the mean number of (expected) wins.   If a team is good and expects to win 90% of its games, the standard deviation will be much smaller than if a team is mediocre and expects to win only 50%.   So, winning one game more than expected will signify greater "luck" (or surprise us more) for a very good team than for a mediocre one.*

 

*suppose then that you measure such "luck" as the deviation from the expected number of wins divided by the std dev.  Say then number of games in the season is  n=16..  Suppose that all the games were against equivalent opponents, and the win probability for each game were p=7/8  for the very good team vs p=1/2 for the mediocre team.  Then the std dev (=  (n*p*(1-p))^(.5)) would be about 50% lower in the former case, resulting in a much greater "luck" value for winning each additional game beyond expectations.  .

Of course, if the very good team goes 16-0 (vs 12-4 expected) and the mediocre one goes 12-4 (vs 8-8 expected), you might also want to revise your estimates of p.  That would change the numbers a bit, but under any reasonable assumptions, still result in a greater "luck" value for the very good team. 

michelin

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